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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
The Forces

Concepts Of Physics MCQ Edition [Volume 1] · Physics · The Forces

The weight of an object is defined as the force with which the...

The weight of an object is defined as the force with which the earth attracts it. Determine the weight of the moon given the following data: universal constant of gravitation G=6.67×10−11 N-m2/kg2G = 6.67 \times 10^{-11} \text{ N-m}^2/\text{kg}^2, mass of the moon =7.36×1022 kg= 7.36 \times 10^{22} \text{ kg}, mass of the earth =6×1024 kg= 6 \times 10^{24} \text{ kg}, and the distance between the earth and the moon =3.8×105 km= 3.8 \times 10^{5} \text{ km}.

Options

  1. A4×1020 N4 \times 10^{20} \text{ N}
  2. B2×1026 N2 \times 10^{26} \text{ N}
  3. C7.8×1027 N7.8 \times 10^{27} \text{ N}
  4. D2×1020 N2 \times 10^{20} \text{ N}

Correct answer

D. 2×1020 N2 \times 10^{20} \text{ N}

Step-by-step solution

The weight of the moon is defined as the gravitational force exerted by the earth on the moon.

F=GMeMmr2F = \dfrac{G M_e M_m}{r^2}

Substituting the given values:

F=6.67×10−11×6×1024×7.36×1022(3.8×108)2F = \dfrac{6.67 \times 10^{-11} \times 6 \times 10^{24} \times 7.36 \times 10^{22}}{(3.8 \times 10^8)^2}

F=294.55×103514.44×1016F = \dfrac{294.55 \times 10^{35}}{14.44 \times 10^{16}}

F≈20.4×1019 N=2.04×1020 NF \approx 20.4 \times 10^{19} \text{ N} = 2.04 \times 10^{20} \text{ N}

The closest value is 2×1020 N2 \times 10^{20} \text{ N}.
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