Water flows through a horizontal tube of variable cross section as shown in the figure. The cross-sectional areas at A and B are 4 mm ^2 and 2 mm ^2 respectively. If 1 cc of water enters the tube per second through A , determine the speed of the water at A .

Step-by-step solution

Given the volume flow rate Q = 1 cc/s = 1 cm ^3/ s . The cross-sectional area at A is A_A = 4 mm ^2 . Converting the area into cm ^2 : A_A = 4 10⁻² cm ^2 From the equation of continuity, the volume flow rate is given by: Q = A_A v_A Substituting the given values to find the speed of water at A ( v_A ): v_A = Q A_A = 1 4 10⁻² = 100 4 = 25 cm/s