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Concepts Of Physics MCQ Edition [Volume 1]PhysicsGeometrical Optics

A candle flame 1.6 cm high is imaged in a ball bearing of diameter 0.4 cm . If the ball bearing is 20 cm away from the flame, determine the location and the height of the image.

Options

  1. A1.0 mm outside the ball bearing, 0.08 mm
  2. B2.0 mm inside the ball bearing, 0.16 mm
  3. C1.0 mm inside the ball bearing, 0.08 mm
  4. D0.1 mm inside the ball bearing, 0.008 mm

Correct answer

C. 1.0 mm inside the ball bearing, 0.08 mm

Step-by-step solution

The ball bearing acts as a convex mirror. Radius of curvature R = 0.4 2 = 0.2 cm . Focal length f = R 2 = +0.1 cm . Object distance u = -20 cm . Using the mirror formula: 1 v + 1 u = 1 f 1 v - 1 20 = 1 0.1 = 10 1 v = 10 + 1 20 = 201 20 v = 20 201 cm 0.1 cm = 1.0 mm Since v > 0 , the image is virtual and formed 1.0 mm inside the ball bearing. Magnification m = - v u m = - 20/201 -20 = 1 201 Height of the image h_i = m h_o h_i = 1 201 1.6 cm 1.6 200 cm = 0.008 cm = 0.08 mm

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