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Concepts Of Physics MCQ Edition [Volume 1]PhysicsLight Waves

White coherent light ( 400 nm – 700 nm ) is passed through the slits of a Young's double slit experiment. The separation between the slits is 0.5 mm and the screen is situated 50 cm away from the slits. A hole exists in the screen at a location 1.0 mm away (along the width of the fringes) from the central line. Determine which wavelength(s) will have a strong intensity in the light emerging from the hole.

Options

  1. A450 nm and 650 nm
  2. B500 nm only
  3. C500 nm and 600 nm
  4. D400 nm and 667 nm

Correct answer

D. 400 nm and 667 nm

Step-by-step solution

Given parameters are: Slit separation, d = 0.5 mm = 0.5 10⁻³ m Distance to screen, D = 50 cm = 0.5 m Position of the hole, y = 1.0 mm = 1.0 10⁻³ m The path difference x at a distance y from the central maximum is given by: x = y d D Substituting the given values: x = (1.0 10⁻³) (0.5 10⁻³) 0.5 m x = 1.0 10⁻⁶ m = 1000 nm For strong intensity (constructive interference), the path difference must be an integer multiple of the wavelength : x = n where n = 1, 2, 3, Therefore, the possible wavelengths are: = x n = 1000 n

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