A nearsighted person is unable to see objects beyond 25 cm . Assuming the separation of the glass from the eye is 1 cm , determine the power of the lens required to view distant objects.

Step-by-step solution

For viewing distant objects, the object distance is u = - . The far point of the nearsighted eye is at 25 cm from the eye. Since the lens is placed 1 cm from the eye, the image must be formed at the far point. Thus, the image distance from the lens is v = -(25 - 1) cm = -24 cm = -0.24 m . Using the lens formula: 1 f = 1 v - 1 u 1 f = 1 -0.24 - 1 - f = -0.24 m The power of the lens is given by: P = 1 f = 1 -0.24 = -4.166 D -4.2 D