A flywheel with a moment of inertia of 5.0 kg-m ^2 is rotated at a speed of 60 rad/s . Due to friction at the axle, it comes to rest in 5.0 minutes . Determine the average torque of the friction.

Step-by-step solution

Given moment of inertia, I = 5.0 kg-m ^2 Initial angular velocity, _i = 60 rad/s Final angular velocity, _f = 0 rad/s Time taken, t = 5.0 minutes = 300 s Using the equation of rotational kinematics, _f = _i + t 0 = 60 + (300) = -0.2 rad/s ^2 The magnitude of the average torque of friction is given by = I | | = 5.0 0.2 = 1.0 N-m