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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Rotational Mechanics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rotational Mechanics

A square plate of mass 120 ext g and edge 5.0 ext cm has a uniform...

A square plate of mass 120extg120 ext{ g} and edge 5.0extcm5.0 ext{ cm} has a uniform angular acceleration of 0.2extrad/s20.2 ext{ rad/s}^2. Calculate the torque on the plate if it rotates about a diagonal with the same angular acceleration.

Options

  1. A5.0×10−6 N m5.0 \times 10^{-6} \text{ N m}
  2. B1.0×10−5 N m1.0 \times 10^{-5} \text{ N m}
  3. C2.0×10−5 N m2.0 \times 10^{-5} \text{ N m}
  4. D8.0×10−6 N m8.0 \times 10^{-6} \text{ N m}

Correct answer

A. 5.0×10−6 N m5.0 \times 10^{-6} \text{ N m}

Step-by-step solution

For a square lamina, the moment of inertia about any axis in its plane through the center is I=112ma2I = \dfrac{1}{12} m a^2. Here m=0.12 kgm = 0.12 \text{ kg} and a=0.05 ma = 0.05 \text{ m}. Thus I=112(0.12)(0.052)=2.5×10−5 kg m2I = \dfrac{1}{12}(0.12)(0.05^2) = 2.5 \times 10^{-5} \text{ kg m}^2. The torque is τ=Iα=(2.5×10−5)(0.2)=5.0×10−6 N m\tau = I\alpha = (2.5 \times 10^{-5})(0.2) = 5.0 \times 10^{-6} \text{ N m}.
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