A particle having a mass of 10 g oscillates according to the equation x = (2.0 cm ) [(100 s ⁻¹) t + /6] . Determine the amplitude, the time period, and the spring constant for this motion.

Step-by-step solution

Comparing the given equation x = (2.0 cm ) [(100 s ⁻¹) t + /6] with the standard equation of SHM x = A ( t + ) , we get: Amplitude A = 2.0 cm Angular frequency = 100 rad/s Time period T = 2 = 2 100 0.063 s Spring constant k = m ^2 = (10 10⁻³ kg )(100 rad/s )^2 = 100 N/m