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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Simple Harmonic Motion

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Simple Harmonic Motion

Determine the time period of the oscillation of mass m and the...

Determine the time period of the oscillation of mass mm and the equivalent spring constant of the pair of springs for the rightmost arrangement shown in the figure.
Determine the time period of the oscillation of mass m and the equivalent spring constant of the pair of springs for

Options

  1. Aπm(k1+k2)k1k2\pi \sqrt{\dfrac{m(k_1 + k_2)}{k_1 k_2}} and k1k2k1+k2\dfrac{k_1 k_2}{k_1 + k_2}
  2. B2πm∣k1−k2∣k1k22\pi \sqrt{\dfrac{m|k_1 - k_2|}{k_1 k_2}} and k1k2∣k1−k2∣\dfrac{k_1 k_2}{|k_1 - k_2|}
  3. C2πm(k1+k2)k1k22\pi \sqrt{\dfrac{m(k_1 + k_2)}{k_1 k_2}} and k1k2k1+k2\dfrac{k_1 k_2}{k_1 + k_2}
  4. D2πmk1+k22\pi \sqrt{\dfrac{m}{k_1 + k_2}} and k1+k2k_1 + k_2

Correct answer

C. 2πm(k1+k2)k1k22\pi \sqrt{\dfrac{m(k_1 + k_2)}{k_1 k_2}} and k1k2k1+k2\dfrac{k_1 k_2}{k_1 + k_2}

Step-by-step solution

In the rightmost arrangement (c), the two springs with spring constants k1k_1 and k2k_2 are connected in series.

For springs in series, the equivalent spring constant keqk_{eq} is given by:

1keq=1k1+1k2\dfrac{1}{k_{eq}} = \dfrac{1}{k_1} + \dfrac{1}{k_2}

keq=k1k2k1+k2k_{eq} = \dfrac{k_1 k_2}{k_1 + k_2}

The time period TT of oscillation for a mass mm attached to a spring system is:

T=2πmkeqT = 2\pi \sqrt{\dfrac{m}{k_{eq}}}

Substituting the value of keqk_{eq}:

T=2πmk1k2k1+k2=2πm(k1+k2)k1k2T = 2\pi \sqrt{\dfrac{m}{\dfrac{k_1 k_2}{k_1 + k_2}}} = 2\pi \sqrt{\dfrac{m(k_1 + k_2)}{k_1 k_2}}
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