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For the following Friedel Craft's alkylation reaction, which of the statements are correct? A. Major product is n-propyl benzene. B. iso-propyl carbocation intermediate is also generated. C. Multiple substitution is inevitable. D. Introducing electron-donating substituent on benzene will not produce any alkyl benzene. Choose the correct answer from the options given below:

Options

  1. AA and D only
  2. BB and C only
  3. CA and C only
  4. DB and D only

Correct answer

B. B and C only

Step-by-step solution

In the given Friedel-Crafts alkylation reaction, 1 -chloropropane reacts with anhydrous AlCl ₃ to initially form a primary carbocation, the n -propyl carbocation ( CH ₃- CH ₂- CH ₂^+ ). This primary carbocation is less stable and undergoes a 1,2 -hydride shift to form a more stable secondary carbocation, the iso-propyl carbocation ( CH ₃- CH ^+- CH ₃ ). Therefore, statement B is correct. The iso-propyl carbocation then acts as an electrophile and attacks the benzene ring, yielding iso-propylbenzene (cumene) as the

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