A certain clock's pendulum has a time period of 2.04 s . How fast or slow will the clock run over a 24 -hour period?

Step-by-step solution

A standard seconds pendulum has a time period T = 2 s . The given pendulum has a time period T' = 2.04 s . Since T' > T , the pendulum takes more time to complete one oscillation, meaning the clock will run slow. In a true time of 24 hours ( 24 3600 = 86400 s ), the number of oscillations made by the pendulum is: n = 86400 2.04 Since the clock registers 2 s for every oscillation, the time shown by the clock in 24 hours is: t_ clock = n 2 = 86400 2.04 2 = 172800 2.04 s The time lost by the clock in 24 hours is the d