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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Simple Harmonic Motion

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Simple Harmonic Motion

A simple pendulum of length l is attached to the ceiling of an...

A simple pendulum of length ll is attached to the ceiling of an elevator. Determine the time period of small oscillations if the elevator is going up with an acceleration a0a_0.

Options

  1. A2πlg−a02\pi \sqrt{\dfrac{l}{g - a_0}}
  2. B2πlg2\pi \sqrt{\dfrac{l}{g}}
  3. C2πlg2+a022\pi \sqrt{\dfrac{l}{\sqrt{g^2 + a_0^2}}}
  4. D2πlg+a02\pi \sqrt{\dfrac{l}{g + a_0}}

Correct answer

D. 2πlg+a02\pi \sqrt{\dfrac{l}{g + a_0}}

Step-by-step solution

In the frame of reference of the elevator accelerating upwards with an acceleration a0a_0, a pseudo force ma0ma_0 acts downwards on the pendulum bob of mass mm.

The true gravitational force mgmg also acts downwards.

The effective weight of the bob is Weff=mg+ma0=m(g+a0)W_{\text{eff}} = mg + ma_0 = m(g + a_0).

The effective acceleration due to gravity is geff=g+a0g_{\text{eff}} = g + a_0.

The time period of a simple pendulum is given by T=2πlgeffT = 2\pi \sqrt{\dfrac{l}{g_{\text{eff}}}}.

Substituting the value of geffg_{\text{eff}}, we get T=2πlg+a0T = 2\pi \sqrt{\dfrac{l}{g + a_0}}.
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