As illustrated in the figure, the upper wire is constructed from...

Both the steel and copper wires are connected in series and support the same load, so they experience the same tension $T$.

Given that both wires have an equal cross-sectional area $A$, the longitudinal stress $\sigma$ in both wires is the same:

$\sigma = \dfrac{T}{A}$

From Hooke's law, the longitudinal strain $\epsilon$ is given by:

$\epsilon = \dfrac{\sigma}{Y}$

where $Y$ is the Young's modulus of the material. The ratio of the longitudinal strain in the copper wire to that in the steel wire is:

$\dfrac{\epsilon_c}{\epsilon_s} = \dfrac{\sigma / Y_c}{\sigma / Y_s} = \dfrac{Y_s}{Y_c}$

Using the standard values of Young's modulus for steel and copper:
$Y_s = 2.0 \times 10^{11} \text{ N/m}^2$
$Y_c = 1.3 \times 10^{11} \text{ N/m}^2$

Substituting these values into the ratio:

$\dfrac{\epsilon_c}{\epsilon_s} = \dfrac{2.0 \times 10^{11}}{1.3 \times 10^{11}} = \dfrac{20}{13} \approx 1.538$

Rounding to two decimal places, we get $1.54$.

Answer: $1.54$