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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Sound Waves

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Sound Waves

A closed organ pipe can vibrate with a minimum frequency of 500 Hz...

A closed organ pipe can vibrate with a minimum frequency of 500 Hz500 \text{ Hz}. Determine the length of the tube. The speed of sound in air is 340 m s−1340 \text{ m s}^{-1}.

Options

  1. A68 cm68 \text{ cm}
  2. B34 cm34 \text{ cm}
  3. C17 cm17 \text{ cm}
  4. D8.5 cm8.5 \text{ cm}

Correct answer

C. 17 cm17 \text{ cm}

Step-by-step solution

The minimum frequency of vibration for a closed organ pipe corresponds to its fundamental frequency, which is given by the formula:

f=v4Lf = \dfrac{v}{4L}

Substituting the given values, f=500 Hzf = 500 \text{ Hz} and v=340 m s−1v = 340 \text{ m s}^{-1}:

500=3404L500 = \dfrac{340}{4L}

L=3404×500L = \dfrac{340}{4 \times 500}

L=3402000=0.17 mL = \dfrac{340}{2000} = 0.17 \text{ m}

L=17 cmL = 17 \text{ cm}
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