Concepts Of Physics MCQ Edition [Volume 1]PhysicsSound Waves

A closed organ pipe can vibrate with a minimum frequency of 500 Hz . Determine the length of the tube. The speed of sound in air is 340 m s ⁻¹ .

Options

A68 cm
B34 cm
C17 cm
D8.5 cm

Correct answer

C. 17 cm

Step-by-step solution

The minimum frequency of vibration for a closed organ pipe corresponds to its fundamental frequency, which is given by the formula: f = v 4L Substituting the given values, f = 500 Hz and v = 340 m s ⁻¹ : 500 = 340 4L L = 340 4 500 L = 340 2000 = 0.17 m L = 17 cm

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