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Concepts Of Physics MCQ Edition [Volume 1]PhysicsSound Waves

In a standing wave pattern within a vibrating air column, nodes are formed at a distance of 40 cm . If the speed of sound in air is 328 m s ⁻¹ , determine the frequency of the source.

Options

  1. A4.1 Hz
  2. B410 Hz
  3. C820 Hz
  4. D205 Hz

Correct answer

B. 410 Hz

Step-by-step solution

The distance between two consecutive nodes in a standing wave is 2 . Given that nodes are formed at a distance of 40 cm , we have: 2 = 40 cm = 0.4 m = 0.8 m The speed of sound is given as v = 328 m s ⁻¹ . The frequency of the source is: f = v = 328 0.8 = 410 Hz

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