In a standing wave pattern within a vibrating air column, nodes are formed at a distance of 40 cm . If the speed of sound in air is 328 m s^ -1 , determine the frequency of the source.

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Quantrex Academy · Accepted Answer

Correct answer: B. 410 Hz

The distance between two consecutive nodes in a standing wave is

\dfrac{\lambda}{2}

.

Given that nodes are formed at a distance of

40 \text{ cm}

, we have:

\dfrac{\lambda}{2} = 40 \text{ cm} = 0.4 \text{ m}

\lambda = 0.8 \text{ m}

The speed of sound is given as

v = 328 \text{ m s}^{-1}

.

The frequency of the source is:

f = \dfrac{v}{\lambda} = \dfrac{328}{0.8} = 410 \text{ Hz}

In a standing wave pattern within a vibrating air column, nodes are...

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