Concepts Of Physics MCQ Edition [Volume 1]PhysicsSound Waves
In a vibrating air column, the distance between a node and the adjacent antinode is 25 cm . If the speed of sound in air is 340 m s ⁻¹ , determine the frequency of vibration of the air column.
Options
- A1360 Hz
- B680 Hz
- C340 Hz
- D170 Hz
Correct answer
C. 340 Hz
Step-by-step solution
The distance between a node and the adjacent antinode is 4 . 4 = 25 cm = 0.25 m = 4 0.25 m = 1 m The frequency of vibration is given by f = v . Substituting the given values: f = 340 1 = 340 Hz