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JEE Main 202623 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
23 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Hydrocarbons

JEE Main 2026 · 23 January · Morning Shift · Chemistry · Hydrocarbons

But-2-yne and hydrogen (one mole each) are separately treated with...

But-2-yne and hydrogen (one mole each) are separately treated with (i) Pd/C\mathrm{Pd} / \mathrm{C} and (ii) Na/liq.NH3\mathrm{Na} / \mathrm{liq}. \mathrm{NH}_{3} to give the products X and Y respectively.
But-2-yne and hydrogen (one mole each) are separately treated with (i) Pd / C and (ii) Na / liq. NH_ 3 to give the
Identify the incorrect statements.
A. XX and YY are stereoisomers.
B. Dipole moment of X is zero.
C. Boiling point of XX is higher than YY.
D. X and Y react with O3/Zn+H2O\mathrm{O}_{3} / \mathrm{Zn}+\mathrm{H}_{2} \mathrm{O} to give different products.
Choose the correct answer from the options given below :

Options

  1. AB and D Only
  2. BA and C Only
  3. CA and B Only
  4. DB and C Only

Correct answer

A. B and D Only

Step-by-step solution

But-2-yne (CH3−C≡C−CH3CH_3-C\equiv C-CH_3) undergoes partial hydrogenation.
Reaction with Pd/CPd/C (Lindlar-like conditions for 1 mole H2H_2) gives cis-but-2-ene as product XX.
Reaction with Na/liq.NH3Na/liq. NH_3 (Birch reduction) gives trans-but-2-ene as product YY.
Statement A: XX (cis)andYand Y (trans) are geometrical isomers, hence stereoisomers. This is correct.
Statement B: Cis-but-2-ene (XX) has a non-zero dipole moment (μ≠0\mu \neq 0) due to the additive nature of bond moments, while trans-but-2-ene (YY) has zero dipole moment (μ=0\mu = 0) due to symmetry. Thus, statement B is incorrect.
Statement C: Cis-isomers generally have higher boiling points than trans-isomers due to higher dipole-dipole interactions. So, B.P. of X>YX > Y. This is correct.
Statement D: Reductive ozonolysis (O3/Zn,H2OO_3/Zn, H_2O) of both cis-but-2-ene and trans-but-2-ene yields the same product, ethanal (CH3CHOCH_3CHO). Thus, statement D is incorrect.
The incorrect statements are B and D.
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