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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Sound Waves

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Sound Waves

Travelling towards a cliff, a car moves with a speed of 54 km h^ -1...

Travelling towards a cliff, a car moves with a speed of 54 km h−154 \text{ km h}^{-1}. The car's horn emits sound at a frequency of 400 Hz400 \text{ Hz}, and the speed of sound is 335 m s−1335 \text{ m s}^{-1}. Calculate the wavelength of the sound wave after it is reflected from the cliff.

Options

  1. A80 cm80 \text{ cm}
  2. B83.75 cm83.75 \text{ cm}
  3. C76.6 cm76.6 \text{ cm}
  4. D87.5 cm87.5 \text{ cm}

Correct answer

A. 80 cm80 \text{ cm}

Step-by-step solution

Speed of the car, vc=54 km h−1=54×518 m s−1=15 m s−1v_c = 54 \text{ km h}^{-1} = 54 \times \dfrac{5}{18} \text{ m s}^{-1} = 15 \text{ m s}^{-1}

Frequency of the horn, f0=400 Hzf_0 = 400 \text{ Hz}

Speed of sound, v=335 m s−1v = 335 \text{ m s}^{-1}

The apparent frequency of the sound reaching the cliff is given by the Doppler effect for a moving source and stationary observer:

f' = f_0 \left(\dfrac{v}{v - v_c} \right)

The cliff acts as a stationary source reflecting the sound at this frequency f′f'. The wavelength of the reflected sound wave is:

λ′=\lambda' =\dfrac{v}{f'} = \dfrac{v - v_c}{f_0}

Substituting the given values:

λ′=\lambda' =\dfrac{335 - 15}{400}

λ′=\lambda' =\dfrac{320}{400} =0.8 m0.8 \text{ m}

λ′=80 cm\lambda' = 80 \text{ cm}
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