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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Sound Waves

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Sound Waves

Travelling towards a cliff, a car moves with a speed of 54 km h^ -1...

Travelling towards a cliff, a car moves with a speed of 54 km h−154 \text{ km h}^{-1}. The car's horn emits sound at a frequency of 400 Hz400 \text{ Hz}, and the speed of sound is 335 m s−1335 \text{ m s}^{-1}. What frequency does a person sitting inside the car hear for the reflected sound wave?

Options

  1. A456.25 Hz456.25 \text{ Hz}
  2. B400 Hz400 \text{ Hz}
  3. C418.75 Hz418.75 \text{ Hz}
  4. D437.5 Hz437.5 \text{ Hz}

Correct answer

D. 437.5 Hz437.5 \text{ Hz}

Step-by-step solution

Speed of the car, vc=54 km h−1=54×518 m s−1=15 m s−1v_c = 54 \text{ km h}^{-1} = 54 \times \dfrac{5}{18} \text{ m s}^{-1} = 15 \text{ m s}^{-1}

Frequency of the horn, f0=400 Hzf_0 = 400 \text{ Hz}

Speed of sound, v=335 m s−1v = 335 \text{ m s}^{-1}

The sound is reflected from the cliff. The cliff acts as a stationary observer for the incident sound and as a stationary source for the reflected sound.

The apparent frequency heard by the person in the car is given by the Doppler effect formula for a source and observer approaching each other:

f' = f_0 \left(\dfrac{v + v_c}{v - v_c} \right)

Substituting the given values:

f′=400(335+15335−15)f' = 400 \left( \dfrac{335 + 15}{335 - 15} \right)

f' = 400 \left(\dfrac{350}{320} \right)

f′=400×f' = 400 \times\dfrac{35}{32}

f′=12.5×35=437.5 Hzf' = 12.5 \times 35 = 437.5 \text{ Hz}
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