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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Sound Waves

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Sound Waves

As shown in the figure, a source of sound moves along the X-axis at...

As shown in the figure, a source of sound moves along the X-axis at a speed of 22 m s−122 \text{ m s}^{-1}, continuously emitting a sound of frequency 2.0 kHz2.0 \text{ kHz} that travels in air at a speed of 330 m s−1330 \text{ m s}^{-1}. A listener QQ stands on the Y-axis at a distance of 330 m330 \text{ m} from the origin. At t=0t = 0, the source crosses the origin PP. Determine the time at which the sound emitted from the source at PP reaches the listener QQ.
As shown in the figure, a source of sound moves along the X-axis at a speed of 22 m s^ -1 , continuously emitting a

Options

  1. A0.94 s0.94 \text{ s}
  2. B2 s2 \text{ s}
  3. C1.07 s1.07 \text{ s}
  4. D1 s1 \text{ s}

Correct answer

D. 1 s1 \text{ s}

Step-by-step solution

The sound is emitted when the source crosses the origin PP. According to the given information, the source is at PP at time t=0t = 0.

The distance between the origin PP and the listener QQ is d=330 md = 330 \text{ m}.

The speed of sound in air is v=330 m s−1v = 330 \text{ m s}^{-1}. Note that the speed of sound in a medium is independent of the speed of the source.

The time taken for the sound to travel from PP to QQ is given by:
t=DistanceSpeed of soundt = \dfrac{\text{Distance}}{\text{Speed of sound}}

t=330 m330 m s−1=1 st = \dfrac{330 \text{ m}}{330 \text{ m s}^{-1}} = 1 \text{ s}

Since the sound was emitted at t=0t = 0, it reaches the listener QQ at t=1 st = 1 \text{ s}.
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