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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Sound Waves

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Sound Waves

A source of sound moves along the X-axis at a speed of 22 m s^ -1 ,...

A source of sound moves along the X-axis at a speed of 22 m s−122 \text{ m s}^{-1}, continuously emitting a sound of frequency 2.0 kHz2.0 \text{ kHz} that travels in air at a speed of 330 m s−1330 \text{ m s}^{-1}. A listener QQ stands on the Y-axis at a distance of 330 m330 \text{ m} from the origin. At t=0t = 0, the source crosses the origin PP. Where will the source be located at the instant the sound emitted from PP reaches the listener?

Options

  1. Aat x=330 mx = 330 \text{ m}
  2. Bat x=−22 mx = -22 \text{ m}
  3. Cat x=0 mx = 0 \text{ m}
  4. Dat x=22 mx = 22 \text{ m}

Correct answer

D. at x=22 mx = 22 \text{ m}

Step-by-step solution

Given:
Speed of the source, vs=22 m s−1v_s = 22 \text{ m s}^{-1}
Speed of sound, v=330 m s−1v = 330 \text{ m s}^{-1}
Distance of listener QQ from the origin PP, d=330 md = 330 \text{ m}

The time taken by the sound to travel from the origin PP to the listener QQ is:
t=dv=330330=1 st = \dfrac{d}{v} = \dfrac{330}{330} = 1 \text{ s}

During this time, the distance traveled by the source along the positive X-axis is:
x=vs×t=22×1=22 mx = v_s \times t = 22 \times 1 = 22 \text{ m}

Therefore, the source will be located at x=22 mx = 22 \text{ m} when the sound emitted from PP reaches the listener.
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