A person slowly slides a block of weight 100 N up a smooth incline of inclination 37^ . If the driving force is applied parallel to the incline, determine the work done by the person in moving the block through a distance of 2.0 m .

Step-by-step solution

Weight of the block, mg = 100 N Inclination of the plane, = 37^ Distance moved, s = 2.0 m Since the block is moved slowly, the net force on the block is zero. The driving force F applied by the person balances the component of gravity along the incline. F = mg F = 100 37^ = 100 3 5 = 60 N Work done by the person is the work done by the driving force. W = Fs = 60 2.0 = 120 J