A person slowly slides a block of weight 100 N up a smooth incline...

Weight of the block, $mg = 100 \text{ N}$

Inclination of the plane, \theta = 37^{}^{{}^{\circ}}

Distance moved, $s = 2.0 \text{ m}$

Since the block is moved slowly, the net force on the block is zero. The driving force $F$ applied by the person balances the component of gravity along the incline.

$F = mg \sin \theta$

F = 100 \sin 37^{}^{{}^{\circ}} = 100 \times \dfrac{3}{5} = 60 \text{ N}

Work done by the person is the work done by the driving force.

$W = Fs = 60 \times 2.0 = 120 \text{ J}$