A block of mass 2.0 kg is pushed down an inclined plane of inclination 37^ by a 20 N force acting parallel to the incline. It is observed that the block travels on the incline with an acceleration of 10 m/s ^2 . Assuming the block starts from rest, determine the work done by the applied force during the first second. Take g = 10 m/s ^2 .

Step-by-step solution

Given initial velocity u = 0 , acceleration a = 10 m/s ^2 , and time t = 1 s . The displacement of the block in the first second is calculated using the equation of motion: s = ut + 1 2 at^2 s = 0 + 1 2 (10)(1)^2 = 5 m The applied force is F = 20 N , acting parallel to the inclined plane in the direction of motion. The work done by the applied force is: W = Fs W = 20 5 = 100 J