Water descending from a 50 m high fall is utilized to generate electric energy. If 1.8 × 10^5 kg of water falls per hour and half of the gravitational potential energy can be converted into electric energy, determine

Question

Quantrex Academy · Accepted Answer

Correct answer: B. 125

Mass of water falling per second, (m)/(t) = (1.8 × 10^5)/(3600) = 50 kg/s Total power available from the falling water is P = (mgh)/(t) Taking g = 10 m/s^2 , we get: P = 50 × 10 × 50 = 25000 W Electric power generated is half of the available power: P_ elec = (25000)/(2) = 12500 W Number of 100 W lamps that can be lit is: n = (12500)/(100) = 125

Water descending from a 50 m high fall is utilized to generate...

Options

Correct answer

Step-by-step solution

More from Work and Energy