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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Work and Energy

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Work and Energy

A water pump extracts water from a depth 10 m below the ground. The...

A water pump extracts water from a depth 10 m10 \text{ m} below the ground. The water is pumped up at a rate of 30 kg/minute30 \text{ kg/minute} with negligible velocity. Determine the minimum horsepower the engine must possess to accomplish this.

Options

  1. A4949
  2. B0.0660.066
  3. C0.130.13
  4. D3.943.94

Correct answer

B. 0.0660.066

Step-by-step solution

The work done by the pump in lifting water is equal to the change in potential energy of the water.

Given:
Mass of water pumped per minute, m=30 kgm = 30 \text{ kg}
Time, t=1 minute=60 st = 1 \text{ minute} = 60 \text{ s}
Depth, h=10 mh = 10 \text{ m}
Acceleration due to gravity, g=9.8 m/s2g = 9.8 \text{ m/s}^2

The power required in watts is given by:
P=mghtP = \dfrac{mgh}{t}

Substituting the given values:
P=30×9.8×1060=49 WP = \dfrac{30 \times 9.8 \times 10}{60} = 49 \text{ W}

To convert the power into horsepower, we use the conversion 1 hp=746 W1 \text{ hp} = 746 \text{ W}.

P=49746 hp≈0.066 hpP = \dfrac{49}{746} \text{ hp} \approx 0.066 \text{ hp}
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