Observe the setup illustrated in the figure. The system is released from rest, and the block of mass 1.0 kg is observed to possess a speed of 0.3 m/s after it has descended through a distance of 1 m . Determine the coefficient of kinetic friction between the block and the table.

Step-by-step solution

Let a₁ and v₁ be the acceleration and velocity of the 1.0 kg block, and a₂ and v₂ be the acceleration and velocity of the 4.0 kg block. From the constraint of the movable pulley, when the 1.0 kg block descends by a distance h , the 4.0 kg block moves by a distance 2h . Thus, v₂ = 2v₁ and a₂ = 2a₁ . Given that the 1.0 kg block descends by h = 1 m and attains a speed of v₁ = 0.3 m/s , we can find its acceleration using the kinematic equation: v₁^2 = u^2 + 2a₁ h (0.3)^2 = 0 + 2a₁(1) 0.09 = 2a₁ a₁ = 0.045 m/s ^2 The ac