A small block of mass 200 g is situated at the top of a...

Since the incline is frictionless, the mechanical energy of the block is conserved.

Loss in potential energy equals the gain in kinetic energy.

$mgh = \dfrac{1}{2}mv^2$

$v = \sqrt{2gh}$

The speed is independent of the mass of the block and the length of the incline.

Substituting the given values $g = 10 \text{ m/s}^2$ and $h = 3.2 \text{ m}$:

$v = \sqrt{2 \times 10 \times 3.2}$

$v = \sqrt{64} = 8.0 \text{ m/s}$