A slide in a park possesses a total length of 10 ext m and a height of 8.0 ext m . A vertical ladder is provided to reach the top. A boy weighing 200 ext N ascends the ladder to the upper end of the slide, then slides down to the ground. The slide offers an average friction equal to three tenths of his weight. Calculate the work done by the slide on the boy as he comes down. Neglect any work done by forces inside the

Step-by-step solution

Given: Length of the slide, s = 10 m Weight of the boy, W = 200 N Average friction force, f = 3 10 W = 3 10 200 = 60 N The slide exerts two forces on the boy: normal reaction and frictional force. The work done by the normal reaction is zero because it is perpendicular to the direction of motion. The work done by the frictional force is: W_f = -f s W_f = -60 10 = -600 J Total work done by the slide on the boy is: W_ slide = W_N + W_f = 0 - 600 = -600 J