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JEE Main 202529 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
29 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Hydrocarbons

JEE Main 2025 · 29 January · Evening Shift · Chemistry · Hydrocarbons

Isomeric hydrocarbons arrow negative Baeyer's test (Molecular...

Isomeric hydrocarbons →\quad \rightarrow \quad negative Baeyer's test (Molecular formula C9H12\mathrm{C}_9 \mathrm{H}_{12} ) The total number of isomers from above with four different non-aliphatic substitution sites is -

Correct answer

2

Step-by-step solution

 Degree of unsaturation =C+1−H2=9+1−6=4\begin{aligned} \text{ Degree of unsaturation } & =\mathrm{C}+1-\frac{\mathrm{H}}{2} \\ & =9+1-6=4 \end{aligned} Benzene shows negative Baeyer's test Both compounds have four different non-aliphatic substitution sites.
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