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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Light Waves

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Light Waves

The wavefronts of a light wave travelling in vacuum are defined by...

The wavefronts of a light wave travelling in vacuum are defined by x+y+z=cx + y + z = c. The angle formed by the direction of propagation of the light with the X-axis is

Options

  1. A45^{}^{{}^{\circ}}
  2. B90^{}^{{}^{\circ}}
  3. Ccos⁡−1(13)\cos^{-1} \left(\dfrac{1}{\sqrt{3}}\right)
  4. D0^{}^{{}^{\circ}}

Correct answer

C. cos⁡−1(13)\cos^{-1} \left(\dfrac{1}{\sqrt{3}}\right)

Step-by-step solution

The equation of the wavefront is given by x+y+z=cx + y + z = c.

The direction of propagation of a light wave is always perpendicular to its wavefront.

The normal vector to the plane x+y+z=cx + y + z = c represents the direction of propagation, which is n⃗=i^+j^+k^\vec{n} = \hat{i} + \hat{j} + \hat{k}.

The angle α\alpha made by the direction of propagation with the X-axis (direction vector i^\hat{i}) is given by

cos⁡α=n⃗⋅i^∣n⃗∣∣i^∣\cos \alpha = \dfrac{\vec{n} \cdot \hat{i}}{|\vec{n}| |\hat{i}|}

cos⁡α=(i^+j^+k^)⋅i^12+12+1212\cos \alpha = \dfrac{(\hat{i} + \hat{j} + \hat{k}) \cdot \hat{i}}{\sqrt{1^2 + 1^2 + 1^2} \sqrt{1^2}}

cos⁡α=13\cos \alpha = \dfrac{1}{\sqrt{3}}

$\alpha = \cos^{-1} \left(\dfrac{1}{\sqrt{3}}\right)
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