Two objects A and B are projected upward at the same time with identical speeds. The mass of A exceeds the mass of B . Assume that air applies a constant and equal resistive force on both bodies.

Step-by-step solution

Let the initial speed of both objects be u . The retardation of an object of mass m moving upwards under gravity and a constant air resistance F is given by a = g + F m . For object A , a_A = g + F m_A . For object B , a_B = g + F m_B . Since m_A > m_B , we have F m_A The maximum height reached by the object is H = u^2 2a . Since a_A H_B . Thus, object A reaches a greater height than object B .