A projectile fired at an angle of 15^ achieves a range of 50 m . If the projectile is fired with the same speed at an angle of 45^ , its range will be

Step-by-step solution

The horizontal range of a projectile is given by R = u^2 (2 ) g . For the first case, = 15^ and R = 50 m . 50 = u^2 (2 15^ ) g = u^2 (30^ ) g Since (30^ ) = 1 2 , we get: u^2 2g = 50 u^2 g = 100 m For the second case, the projectile is fired with the same speed at an angle ' = 45^ . R' = u^2 (2 45^ ) g = u^2 (90^ ) g Since (90^ ) = 1 , we get: R' = u^2 g = 100 m