A wheel of radius 20 cm is pushed to move on a rough horizontal surface. It travels a distance of 60 cm on the road during the time it completes one revolution about its centre. Assuming the linear and angular accelerations are uniform, the frictional force exerted by the surface on the wheel is

Step-by-step solution

Distance travelled by the wheel in one revolution, s = 60 cm Angle rotated by the wheel in one revolution, = 2 rad Distance the wheel would travel if it were in pure rolling, s_ rolling = R = 20 2 = 40 125.6 cm Since s The velocity of the lowest point of the wheel (point of contact) with respect to the ground is given by v_ contact = v - R . Since v Kinetic friction always opposes the relative motion of the surfaces in contact. Since the point of contact slips backwards, the frictional force exerted by the surface