For a particle undergoing simple harmonic motion, the displacement over one time period is

Step-by-step solution

The displacement of a particle in simple harmonic motion is given by x(t) = A ( t + ) . After one complete time period T = 2 , the position of the particle is: x(t+T) = A ( (t+T) + ) x(t+T) = A ( t + 2 + ) = A ( t + ) = x(t) Since the initial and final positions of the particle are the same after one time period, the net displacement is zero. The total distance traveled over one time period is 4A , but the displacement is zero.