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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Simple Harmonic Motion

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Simple Harmonic Motion

A particle travels along the X-axis described by the equation x = A...

A particle travels along the X-axis described by the equation x=A+Bsin⁡ωtx = A + B \sin\omega t. The motion is simple harmonic with an amplitude of

Options

  1. AA2+B2\sqrt{A^2 + B^2}
  2. BA+BA + B
  3. CBB
  4. DAA

Correct answer

C. BB

Step-by-step solution

The given equation of motion is x=A+Bsin⁡ωtx = A + B \sin\omega t.

Rearranging the terms, we get x−A=Bsin⁡ωtx - A = B \sin\omega t.

This equation represents a simple harmonic motion about the mean position x=Ax = A.

The amplitude of the motion is the maximum displacement from the mean position.

Since the maximum value of sin⁡ωt\sin\omega t is 11, the maximum displacement from the mean position is BB.

Therefore, the amplitude of the simple harmonic motion is BB.
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