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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Simple Harmonic Motion

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Simple Harmonic Motion

In simple harmonic motion, the total mechanical energy of a...

In simple harmonic motion, the total mechanical energy of a spring-mass system is E=12mω2A2E = \dfrac{1}{2} m \omega^2 A^2. Suppose the oscillating particle is swapped out for another particle having double the mass, while the amplitude AA is kept unchanged. The new mechanical energy will

Options

  1. Aremain EE
  2. Bbecome 2E\sqrt{2} E
  3. Cbecome E/2E/2
  4. Dbecome 2E2E

Correct answer

A. remain EE

Step-by-step solution

The total mechanical energy of a spring-mass system is given by E=12mω2A2E = \dfrac{1}{2} m \omega^2 A^2.

For a spring-mass system, the angular frequency is ω=km\omega = \sqrt{\dfrac{k}{m}}, which gives mω2=km \omega^2 = k, where kk is the spring constant.

Substituting this into the energy expression gives E=12kA2E = \dfrac{1}{2} k A^2.

The spring constant kk is a property of the spring and is independent of the mass of the oscillating particle. Since the amplitude AA is kept unchanged, the total mechanical energy depends only on kk and AA.

Therefore, the new mechanical energy will remain EE.
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