A solid is fully immersed in a liquid. The force exerted by the...

The net force exerted by a liquid on a solid immersed in it is the buoyant force.

According to Archimedes' principle, the buoyant force acts in the vertically upward direction and its magnitude is equal to the weight of the liquid displaced by the solid.

$F_{B} = \rho V_{i} g$

where $\rho$ is the density of the liquid, $V_{i}$ is the immersed volume of the solid, and $g$ is the acceleration due to gravity.

Since the buoyant force depends only on the immersed volume and the density of the liquid, it does not change if the orientation of the fully immersed solid is modified or if it is pushed deeper into the liquid.

If the solid is partially withdrawn from the liquid, the immersed volume $V_{i}$ decreases, which causes the buoyant force to decrease.