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JEE Main 20231 FebruaryEvening Shift
Exam
JEE Main
Year
2023
Date
1 February
Shift
Evening Shift
Subject
Chemistry
Chapter
Hydrocarbons

JEE Main 2023 · 1 February · Evening Shift · Chemistry · Hydrocarbons

‘ X ’ is:

‘XX’ is: ‘ X ’ is:

Options

  1. A1 ~g of polymer having molar mass 1,60,000 ~g is dissolved in 800 ~mL water. Calculate the osmotic pressure in pascal
  2. B1 ~g of polymer having molar mass 1,60,000 ~g is dissolved in 800 ~mL water. Calculate the osmotic pressure in pascal
  3. C1 ~g of polymer having molar mass 1,60,000 ~g is dissolved in 800 ~mL water. Calculate the osmotic pressure in pascal
  4. D1 ~g of polymer having molar mass 1,60,000 ~g is dissolved in 800 ~mL water. Calculate the osmotic pressure in pascal

Correct answer

A. 1 ~g of polymer having molar mass 1,60,000 ~g is dissolved in 800 ~mL water. Calculate the osmotic pressure in pascal

Step-by-step solution

When benzene reacts with methylidenecyclohexane, the product X is formed.

‘ X ’ is:

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