A heavy stone is projected from a cliff of height h in a specified direction. The speed at which it strikes the ground

Step-by-step solution

Let the mass of the heavy stone be m , the speed of projection be u , and the height of the cliff be h . By the principle of conservation of mechanical energy, the total energy of the stone at the point of projection is equal to the total energy just before it strikes the ground. Initial mechanical energy, E_i = 1 2 mu^2 + mgh Final mechanical energy, E_f = 1 2 mv^2 Equating the initial and final energies: 1 2 mv^2 = 1 2 mu^2 + mgh v^2 = u^2 + 2gh v = u^2 + 2gh From the above expression, it is clear that the final