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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Work and Energy

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Work and Energy

Two observers are moving relative to one another at a speed v along...

Two observers are moving relative to one another at a speed vv along a straight line. They watch a block of mass mm travelling a distance ll over a rough surface. Which of the following quantities will be identical as measured by the two observers?

Options

  1. AWork done by friction
  2. BTotal work done on the block
  3. CAcceleration of the block
  4. DKinetic energy of the block at time tt

Correct answer

C. Acceleration of the block

Step-by-step solution

Since the two observers are moving relative to each other at a constant speed vv, they are in different inertial frames of reference.

According to Galilean relativity, the acceleration of an object is invariant across all inertial frames. If uu and u′u' are the velocities of the block measured by the two observers, they are related by u′=u−vu' = u - v. Differentiating with respect to time tt, we get du′dt=dudt\dfrac{du'}{dt} = \dfrac{du}{dt} since vv is constant. Thus, a′=aa' = a.

The displacement of the block depends on the frame of reference. Consequently, the work done by friction (W=∫F⋅dxW = \int F \cdot dx) and the total work done will be different for the two observers.

Similarly, the kinetic energy (K=12mu2K = \dfrac{1}{2}mu^2) depends on the observer's frame since velocity is a relative quantity.

Therefore, only the acceleration of the block will be identical as measured by both observers.
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