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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Light Waves

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Light Waves

The speed of light emitted by a source is measured as v_A , v_B ,...

The speed of light emitted by a source is measured as vAv_A, vBv_B, and vCv_C by three observers AA, BB, and CC, respectively. Observer AA travels towards the source and observer CC travels away from the source at an identical speed. Meanwhile, observer BB remains stationary. The entire surrounding space is a vacuum.

Options

  1. AvA<vB<vCv_A < v_B < v_C
  2. BvB=12(vA+vC)v_B = \dfrac{1}{2}(v_A + v_C)
  3. CvA>vB>vCv_A > v_B > v_C
  4. DvA=vB=vCv_A = v_B = v_C

Correct answer

D. vA=vB=vCv_A = v_B = v_C

Step-by-step solution

According to the second postulate of the special theory of relativity, the speed of light in a vacuum is an absolute constant.

It is completely independent of the relative motion between the source of light and the observer.

Therefore, all three observers AA, BB, and CC will measure the exact same speed of light, regardless of whether they are moving towards the source, moving away from it, or remaining stationary.

Thus, we have vA=vB=vCv_A = v_B = v_C.
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