Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
Concepts Of Physics MCQ Edition [Volume 1]PhysicsSimple Harmonic Motion

A particle travels along a circular path with a continuously increasing speed. Its motion is classified as

Options

  1. Aoscillatory
  2. Bsimple harmonic
  3. Cperiodic
  4. Dneither periodic nor oscillatory

Correct answer

D. neither periodic nor oscillatory

Step-by-step solution

The particle moves along a circular path with continuously increasing speed. Since the speed is increasing, the time taken to complete each successive revolution decreases. Thus, the motion does not repeat itself in equal intervals of time, meaning it is not periodic. The motion does not involve moving back and forth about a mean position, so it is not oscillatory. Therefore, the motion is neither periodic nor oscillatory.

Practice Simple Harmonic Motion on Quantrex Academy →

More from Simple Harmonic Motion

At a specific instant, the magnitudes of the position, velocity, and acceleration of a particle undergoing simple harmonic motion are observed to be 2 cm , 1 m/s , and 10 m/s ^2 , For a particle executing simple harmonic motion, the maximum speed and acceleration are 10 cm/s and 50 cm/s ^2 , respectively. Determine the position(s) of the particle when its spA particle having a mass of 10 g oscillates according to the equation x = (2.0 cm ) [(100 s ⁻¹) t + /6] . Determine the amplitude, the time period, and the spring constant for thisA particle undergoes simple harmonic motion having an amplitude of 10 cm . At what distance from the mean position will its kinetic and potential energies be equal?A particle executes simple harmonic motion with an amplitude of 10 cm and a time period of 6 s . At t = 0 , it is located at x = 5 cm and is moving towards the positive x-directionA particle having a mass of 10 g oscillates according to the equation x = (2.0 cm ) [(100 s ⁻¹) t + /6] . Determine the position, the velocity, and the acceleration of the particleA particle begins its motion at t = 0 according to the equation x = 5 (20 t + /3) , where x is in centimetre and t is in second. At what time will the particle first have zero acceA particle starts moving at t = 0 with its position given by the equation x = 5 (20 t + /3) , where x is in centimetre and t is in second. Determine the time when the particle firs Full Simple Harmonic Motion list All Concepts Of Physics MCQ Edition [Volume 1] PYQs