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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Simple Harmonic Motion

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Simple Harmonic Motion

In a simple harmonic motion, which of the following quantities is...

In a simple harmonic motion, which of the following quantities is always positive?

Options

  1. AF⃗⋅a⃗\vec{F} \cdot \vec{a}
  2. Bv⃗⋅r⃗\vec{v} \cdot \vec{r}
  3. Ca⃗⋅r⃗\vec{a} \cdot \vec{r}
  4. DF⃗⋅r⃗\vec{F} \cdot \vec{r}

Correct answer

A. F⃗⋅a⃗\vec{F} \cdot \vec{a}

Step-by-step solution

In simple harmonic motion, the restoring force F⃗\vec{F} and acceleration a⃗\vec{a} are related by Newton's second law as F⃗=ma⃗\vec{F} = m\vec{a}.

Taking the dot product of F⃗\vec{F} and a⃗\vec{a}, we get:

F⃗⋅a⃗=(ma⃗)⋅a⃗=m∣a⃗∣2=ma2\vec{F} \cdot \vec{a} = (m\vec{a}) \cdot \vec{a} = m|\vec{a}|^2 = ma^2

Since mass mm is a positive quantity and the square of the magnitude of acceleration a2a^2 is always non-negative, their product is always positive (or zero at the mean position).

For the other options:

a⃗⋅r⃗=(−ω2r⃗)⋅r⃗=−ω2r2≤0\vec{a} \cdot \vec{r} = (-\omega^2 \vec{r}) \cdot \vec{r} = -\omega^2 r^2 \le 0

F⃗⋅r⃗=(−kr⃗)⋅r⃗=−kr2≤0\vec{F} \cdot \vec{r} = (-k \vec{r}) \cdot \vec{r} = -k r^2 \le 0

v⃗⋅r⃗\vec{v} \cdot \vec{r} can be positive or negative depending on whether the particle is moving away from or towards the mean position.
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