JEE Main202228 Jul 2022Morning ShiftChemistryHydrocarbonsActual
Choose the correct option for the following reactions.
Options
- A' A ' and ' B ' are both Markovnikov addition products.
- B' A ' is Markovnikov product and ' B ' is antiMarkovnikov product.
- C' A ' and ' B ' are both anti-Markovnikov products.
- D' B ' is Markovnikov and ' A ' is anti- Markovnikov product.
Correct answer
B. ' A ' is Markovnikov product and ' B ' is antiMarkovnikov product.
Step-by-step solution
In the first step of hydroboration oxidation, the boron and hydrogen add to the same face of the double bond. In the second step, the OH takes the identical position occupied by the boron. Thus, the OH and H groups that are effectively added to the original double bond are cis. The overall addition takes place in anti Markovnikov's fashion. The reagent is mercury(II) acetate, which dissociates slightly to form + Hg ( OAc ) . + Hg ( OAc ) is the electrophile that adds to the pi bond. • The intermediate is a