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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Work and Energy

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Work and Energy

A particle is subjected to a force of constant magnitude that is...

A particle is subjected to a force of constant magnitude that is always perpendicular to its velocity. The motion of the particle occurs in a plane. It then follows that

Options

  1. Ait moves in a circular path
  2. Bits velocity is constant
  3. Cits acceleration is constant
  4. Dits kinetic energy is constant

Correct answer

D. its kinetic energy is constant

Step-by-step solution

Since the force is always perpendicular to the velocity, the power delivered by the force is zero (F⃗⋅v⃗=0\vec{F} \cdot \vec{v} = 0).

Therefore, the work done by the force is zero, which implies that the kinetic energy and the speed vv of the particle remain constant.

The magnitude of the force is constant, so the magnitude of the acceleration a=Fma = \dfrac{F}{m} is also constant.

Since the force is perpendicular to the velocity, the acceleration is purely centripetal and is given by a=v2Ra = \dfrac{v^2}{R}, where RR is the radius of curvature.

Because both vv and aa are constant, the radius of curvature RR is constant. Motion in a plane with a constant radius of curvature is a circular path.

Since the direction of motion changes continuously, the velocity and acceleration vectors are not constant.
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