In the following reaction ​​​​​​​ The % yield for reaction I is 60 % and that of reaction II is 50 % . The overall yield of the complete reaction is %

Step-by-step solution

Let initial moles of reactant taken = n Total moles obtained for benzene sulphonic acid (with % yield = 60 % ) = 0 . 6   n Moles of benzene sulphonic acid before reaction II = 0 . 6   n Moles obtained for phenol (with % yield = 50 % ) = 0 . 6 × 0 . 5   n = 0 . 3   n So over all % yield of complete reaction = 0 . 3 n n × 100 = 30