Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
Concepts Of Physics MCQ Edition [Volume 2]PhysicsBohr's Model and Physics of the Atom

Determine the smallest wavelength of radiation that can be emitted by hydrogen.

Options

  1. A365 nm
  2. B91 nm
  3. C122 nm
  4. D820 nm

Correct answer

B. 91 nm

Step-by-step solution

The smallest wavelength of radiation emitted by a hydrogen atom corresponds to the maximum energy transition. This maximum energy transition occurs when an electron falls from n = to n = 1 (the series limit of the Lyman series). Using the Rydberg formula: 1 = R ( 1 n₁^2 - 1 n₂^2 ) Substituting n₁ = 1 and n₂ = : 1 = R ( 1 1^2 - 1 ^2 ) = R = 1 R Substituting the value of the Rydberg constant R = 1.097 10^7 m ⁻¹ : = 1 1.097 10^7 m 91.1 10⁻⁹ m = 91.1 nm Thus, the smallest wavelength is approximately 91 nm .

Practice Bohr's Model and Physics of the Atom on Quantrex Academy →

More from Bohr's Model and Physics of the Atom

The Bohr radius is given by a₀ = ₀ h^2 m e^2 . Determine the dimensions of the right-hand side.Determine the wavelength of the radiation emitted by hydrogen during the transition from n = 10 to n = 9 .Determine the wavelength of the radiation emitted by hydrogen during the transition from n = 3 to n = 2 .Determine the wavelength of the radiation emitted by hydrogen during the transition from n = 5 to n = 4 .Determine the smallest wavelength of radiation that can be emitted by He ^+ .Determine the smallest wavelength of radiation that can be emitted by Li ⁺⁺ .Calculate the Rydberg constant by substituting the values of the fundamental constants into its expression.Determine the binding energy of a hydrogen atom when it is in the n = 2 state. Full Bohr's Model and Physics of the Atom list All Concepts Of Physics MCQ Edition [Volume 2] PYQs