Concepts Of Physics MCQ Edition [Volume 2]PhysicsCapacitors
A potential difference of 10 V develops between two conductors when 1.0 10¹² electrons are transferred from one conductor to the other. Determine the capacitance of the two-conductor system.
Options
- A1.6 10⁻⁹ F
- B1.6 10⁻⁷ F
- C1.6 10⁻⁶ F
- D1.6 10⁻⁸ F
Correct answer
D. 1.6 10⁻⁸ F
Step-by-step solution
The charge transferred from one conductor to the other is given by q = ne . Substituting the given values: q = (1.0 10¹²) (1.6 10⁻¹⁹) C = 1.6 10⁻⁷ C The capacitance of the system is given by C = q V . Substituting q = 1.6 10⁻⁷ C and V = 10 V : C = 1.6 10⁻⁷ 10 F = 1.6 10⁻⁸ F