A potential difference of 10 V develops between two conductors when 1.0 × 10^ 12 electrons are transferred from one conductor to the other. Determine the capacitance of the two-conductor system.

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Quantrex Academy · Accepted Answer

Correct answer: D. 1.6 × 10^ -8 F

The charge transferred from one conductor to the other is given by

q = ne

.

Substituting the given values:

q = (1.0 \times 10^{12}) \times (1.6 \times 10^{-19}) \text{ C} = 1.6 \times 10^{-7} \text{ C}

The capacitance of the system is given by

C = \dfrac{q}{V}

.

Substituting

q = 1.6 \times 10^{-7} \text{ C}

and

V = 10 \text{ V}

:

C = \dfrac{1.6 \times 10^{-7}}{10} \text{ F} = 1.6 \times 10^{-8} \text{ F}

A potential difference of 10 V develops between two conductors when...

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