In the circuit shown in the figure, each capacitor has a capacitance of 5.0 F and the battery has an emf of 50 V . Determine the amount of charge that will flow through AB when the switch S is closed.

Step-by-step solution

Let the capacitance of each capacitor be C = 5.0 F and the voltage of the battery be V = 50 V . Before the switch S is closed, the circuit consists of two capacitors in parallel, which are in series with a third capacitor. The equivalent capacitance of the parallel combination is: C_ p = C + C = 5.0 + 5.0 = 10.0 F This combination is in series with the third capacitor C . The initial equivalent capacitance of the entire circuit is: C_ initial = C_ p C C_ p + C = 10.0 5.0 10.0 + 5.0 = 50 15 = 10 3 F The initial char