Concepts Of Physics MCQ Edition [Volume 2]PhysicsCapacitors
A parallel-plate capacitor with a plate area of 25 cm ^2 and a separation of 1.00 mm is connected to a 6.0 V battery. Determine the charge that has flown through the battery and the work done by the battery during this process.
Options
- A6.65 10⁻¹¹ C , 4.0 10⁻¹⁰ J
- B2.66 10⁻¹⁰ C , 1.6 10⁻⁹ J
- C1.33 10⁻¹⁰ C , 8.0 10⁻¹⁰ J
- D1.33 10⁻¹⁰ C , 4.0 10⁻¹⁰ J
Correct answer
C. 1.33 10⁻¹⁰ C , 8.0 10⁻¹⁰ J
Step-by-step solution
The capacitance of the parallel-plate capacitor is given by: C = ₀ A d Substituting the given values: C = 8.85 10⁻¹² 25 10⁻⁴ 1.00 10⁻³ = 2.2125 10⁻¹¹ F The charge that flows through the battery is: Q = CV = 2.2125 10⁻¹¹ 6.0 = 1.3275 10⁻¹⁰ C 1.33 10⁻¹⁰ C The work done by the battery is the product of the charge that flows through it and its electromotive force (voltage): W = QV = 1.3275 10⁻¹⁰ 6.0 = 7.965 10⁻¹⁰ J 8.0 10⁻¹⁰ J